Three bivalue cells forcing a distant elimination. experthard
Whichever value the pivot R7C7 takes, one pincer becomes 3, so R5C9, seeing both pincers, cannot hold it. (Shown on a plain grid.)
Three cells with two candidates each, linked pivot-to-pincers: whichever value the pivot takes, one pincer ends up holding the shared digit. Any cell that sees both pincers can never hold it.